- 1. Entrada, impressão e números
- 2. Números inteiros e flutuantes
- 3. Condições: if-then-else
- 4. Para loop com alcance
- 5. Cordas
- 6. Enquanto loop
- 7. Listas
- 8. Funções e recursão
- 9. Listas bidimensionais (arrays)
- 10. Conjuntos
- 11. Dicionários
- 12. JavaScript
- 13. HTML5 and CSS
- 14. Responsive Design with Bootstrap
- 15. jQuery

# Leap year

## Statement

Given the year number. You need to check if this year is a leap year. If it is, print`LEAP`

, otherwise print `COMMON`

. The rules in Gregorian calendar are as follows:

- a year is a leap year if its number is exactly divisible by 4 and is not exactly divisible by 100
- a year is always a leap year if its number is exactly divisible by 400

**Warning.** The words `LEAP`

and `COMMON`

should be printed all caps.

In all the problems input the data using `input()`

and print the result using `print()`

.